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Hi
I am doing this exercise (2 class problem with 2-dimensional features) and I have solved the linear discriminant function which turns out be y1(x) - y2(x) = 2x1 +2x2
I am having difficulty in finding the class posterior probabilities frm the linear discriminant function obtained.
But I tried this way and got stuck.
We know that yi(x) = ln{p(x|ci)p(Ci)}
from the linear discriminant function obtained
y1(x) = ln{p(x|C1)p(C1)} = 2x1 + 2x2 + y2(x)
ln{p(x|C1)p(C1)} = 2x1 + 2x2 + ln{p(x|C2)p(C2)}
ln[{p(x|C1)p(C1)} - {p(x|C2)p(C2)} = 2x1 + 2x2
Using exponential for both side we get
p(x|C1)p(C1)/p(x|C2)p(C2) = exp(2x1 + 2x2)
p(C1) and p(C2) are constatnt so we can neglect us giving the following
p(x|C1)/p(x|C2)= exp(2x1 + 2x2)
From this point I am not sure how to separate both posterior probabilities.
please help...Thank you
I am doing this exercise (2 class problem with 2-dimensional features) and I have solved the linear discriminant function which turns out be y1(x) - y2(x) = 2x1 +2x2
I am having difficulty in finding the class posterior probabilities frm the linear discriminant function obtained.
But I tried this way and got stuck.
We know that yi(x) = ln{p(x|ci)p(Ci)}
from the linear discriminant function obtained
y1(x) = ln{p(x|C1)p(C1)} = 2x1 + 2x2 + y2(x)
ln{p(x|C1)p(C1)} = 2x1 + 2x2 + ln{p(x|C2)p(C2)}
ln[{p(x|C1)p(C1)} - {p(x|C2)p(C2)} = 2x1 + 2x2
Using exponential for both side we get
p(x|C1)p(C1)/p(x|C2)p(C2) = exp(2x1 + 2x2)
p(C1) and p(C2) are constatnt so we can neglect us giving the following
p(x|C1)/p(x|C2)= exp(2x1 + 2x2)
From this point I am not sure how to separate both posterior probabilities.
please help...Thank you
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