Finding coefficient of kinetic friction on a track with a spring.

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SUMMARY

The discussion focuses on calculating the coefficient of kinetic friction for a 10 kg block moving on a track with a spring. The block is released from a height of 3 meters and travels down a frictionless track before compressing a spring with a force constant of 2250 N/m by 0.3 m. The key conclusion is that the energy lost due to friction can be calculated by comparing the initial and final energy states, leading to a coefficient of kinetic friction of 0.327.

PREREQUISITES
  • Understanding of potential energy (PE) and kinetic energy (KE) concepts
  • Familiarity with the conservation of energy principle
  • Knowledge of spring mechanics, specifically Hooke's Law
  • Basic understanding of friction and its impact on motion
NEXT STEPS
  • Study the conservation of energy in systems with non-conservative forces
  • Learn how to apply Hooke's Law in practical scenarios
  • Explore the calculations for work done by friction
  • Investigate the relationship between energy loss and coefficient of friction
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Physics students, mechanical engineers, and anyone interested in understanding dynamics and energy transfer in mechanical systems.

lykwedontcare
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1. The problem statement

A 10 kg block is released from point A on a track ABCD. The track is frictionless except for the portion BC, of length 6 m. The block travels down the track and hits a spring of force constant k = 2250 N/m and compresses it a distance of 0.3 m from its equilibrium position before coming to rest momentarily. Determine the coefficient of kinetic friction between the track portion BC and the block.

***ADDITIONAL INFO

The height is 3 meters from the slope from A>B, while points B>C>D are completely horizontal.

The Attempt at a Solution



PE = KE

I find at point B the velocity of the block is 7.67 m/s. However I'm unable to figure out the next step.

I started with using KE = PE (spring) and found a difference of about 192 N, which I'm not sure has anything to do with the problem (the difference of the block slowing down?) but am not sure.

I do know the answer is 0.327, so I'm not after an answer, I simply just want to know how to do the problem.

Any direction would be appreciated, the more the better,
Thanks
 
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lykwedontcare said:
1. The problem statement

A 10 kg block is released from point A on a track ABCD. The track is frictionless except for the portion BC, of length 6 m. The block travels down the track and hits a spring of force constant k = 2250 N/m and compresses it a distance of 0.3 m from its equilibrium position before coming to rest momentarily. Determine the coefficient of kinetic friction between the track portion BC and the block.

***ADDITIONAL INFO

The height is 3 meters from the slope from A>B, while points B>C>D are completely horizontal.

The Attempt at a Solution



PE = KE

I find at point B the velocity of the block is 7.67 m/s. However I'm unable to figure out the next step.
That value is correct, although this step is unnecessary.
I started with using KE = PE (spring) and found a difference of about 192 N, which I'm not sure has anything to do with the problem (the difference of the block slowing down?) but am not sure.
If there is a difference between the KE at point B and the PE at point D, then KE at B does not equal the PE at point D. As you note, 192 J (not N) of energy was 'lost' due to work done by friction. Use the definition of this Work to find the friction force and then the friction coefficient.

Note that you can take the start point at A and the end point at D, and get the same answer using the conservation of total energy law.

Also note that (KE + PE)initial = (KE + PE)final, only when conservative forces that do work (such as gravity and springs) are acting. When non-conservative forces (like friction) are acting, energy is transferred out of (or into) the system, due to the work done by such non-conservative forces.
 

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