Finding Displacement Using Impulse Momentum: A Problem with Monkeys and a Pulley

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SUMMARY

The discussion focuses on solving a dynamics problem involving two monkeys and a pulley, utilizing impulse momentum principles. The system consists of a massless rope over a frictionless pulley, with one monkey of mass M and another of mass 2M. The problem requires calculating the displacement of monkey A after monkey B descends 15 feet in 2 seconds. The equations of motion for both monkeys and the pulley are established, but the user encounters difficulties due to the presence of multiple unknowns and the need for kinematic constraints.

PREREQUISITES
  • Understanding of impulse momentum principles in rigid body dynamics
  • Familiarity with Newton's laws of motion
  • Knowledge of kinematics and circular motion
  • Ability to set up and solve systems of equations
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  • Study the application of impulse momentum in rigid body dynamics
  • Learn about kinematic constraints in pulley systems
  • Explore energy conservation principles in mechanical systems
  • Practice solving similar problems involving multiple bodies and forces
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I am having a really hard time with dynamics of rigid bodies, but i think doing this problem will clear up some confusion i have.

Homework Statement


A massless rope hanging over a frictionless pulley of mass M supports two monkeys (one of mass M, the other of mass 2M). The system is released at rest at t = 0. During the following 2 sec, monkey B travels down 15 ft of rope to obtain a massless peanut at P. Monkey A holds tightly to the rope during these two sec. Find the displacement of A during the time interval. Treat the pulley as a uniform cylinder of radius R.
Relevant picture: diagram

Homework Equations


As mentioned in the topic title, the problem has to do with impulse momentum:
∫ƩFy = m(y'f - y'i) [for monkey A]
∫ƩFy = m(y'f - y'i) [for monkey B]
∫ƩM = (I^{c}_{zz}w)_{f} -(I^{c}_{zz}w)_{i} [for the pulley of mass M]

The Attempt at a Solution


This is what I tried to do
(all initial velocities and angular velocities are zero)

For monkey A:
∫^{2}_{0}(T_{1} - Mg) dt = M*y'_{A}_{f}
-> T_{1}*t - Mgt = M*y'_{A}_{f}
-> 2T_{1} -2Mg = M*y'_{A}_{f}

For monkey B:
∫^{2}_{0}(T_{2} - 2Mg) dt = 2M*y'_{B}_{f}
-> T_{2}*t - 2Mgt = 2M*y'_{B}_{f}
-> 2T_{2} - 4Mg = 2M*y'_{B}_{f}

For the pulley:
∫^{2}_{0}(MgR - 2MgR) dt = (I^{c}_{zz}w)_{f}
-> -2MgR = (1/2)MR^{2}w_{f}

From the conclusion of all three sets of equations, I have 5 unknowns, with only three equations
I figure from here I need to some kinematics:
By circular motion, the y'_{A} = R*w_{f}, which helps eliminate one unknown
In addition, there is the length of rope connecting the three bodies, but considering the pulley has mass, I am not sure how to relate the velocities of point A and point B
I believe I get stuck a lot on the kinematic constraints, and here I am not sure how to solve the system of equations I developed

Any help is greatly appreciated
 
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Seems to me this problem is solvable by elementary energy conservation principles.
Were you explicitly asked to analyze in terms of impulse momentum considerations?
 
Yes, the problem is an exercise in using impulse momentum. I know there are other ways to solve it, but I was hoping to clear up some confusion I have with using impulse momentum.
 

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