Finding Distance: Solve for Height from 1.77s Drop Time

  • Thread starter Thread starter mmaggiee
  • Start date Start date
AI Thread Summary
To find the height from which a golf ball was dropped, the time of 1.77 seconds is used with the formula d = vit + 1/2 at^2. Given that the initial velocity (vi) is 0 m/s and acceleration (a) due to gravity is 9.8 m/s², the calculation confirms the height as approximately 15.35 meters. The method and solution are validated by participants in the discussion. This straightforward physics problem effectively demonstrates the application of kinematic equations in real-world scenarios.
mmaggiee
Messages
1
Reaction score
0
Our class dropped a golf ball from an unknown height. The time it took for the golf ball to hit the ground was 1.77 seconds. We are now required to find the height from this information. I'd just like to run over the problem with you guys.

So:

t = 1.77s
vi = 0m/s
acc = 9.8 m/s^2 (Due to gravity, correct?)
d = ?

I'm suspecting that I use the distance formula of:

d= vit + 1/2 at^2

so that the height is:

15.35m?

---

I apologize for the simplicity of the problem, but I'd really appreciate help.
 
Physics news on Phys.org
yes, that's the right approach and the right solution
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top