Finding E, L and Lz from wavefunction

  • Thread starter Thread starter the riddick25
  • Start date Start date
  • Tags Tags
    Wavefunction
the riddick25
Messages
24
Reaction score
0

Homework Statement


We were given the wavefunction for a hydrogen atom (ignoring spin) as shown in the link below
We are asked to find the probability of obtaining E=E1, L^2=2 hbar^2 and Lz=hbar


Homework Equations


http://s633.photobucket.com/albums/uu58/john_sharkey/?action=view&current=equation.jpg


The Attempt at a Solution


i have no idea what equations i would need to find the probabilities of finding these results.
If somebody could point me in the right direction it would be much appreciated.
 
Physics news on Phys.org
That wavefunction is a superposition of two stationary states, namely psi_100 and psi_211. Each stationary state has a definite E, L^2, and Lz: if you know that a particle is in the state psi_100, for example, you will always get E1 when you measure its energy.

This particle is not yet in any state, but when you take a measurement, it randomly collapses into one of the two stationary states. The question is essentially asking what the probability of it collapsing into the state with energy E1 is, and ditto for L^2 and Lz.
 
is the probability of obtaining each stationary state just 2/3 and 1/3 respectively?

Also thank you very much for your help
 
Yup, and you're welcome.
 
##|\Psi|^2=\frac{1}{\sqrt{\pi b^2}}\exp(\frac{-(x-x_0)^2}{b^2}).## ##\braket{x}=\frac{1}{\sqrt{\pi b^2}}\int_{-\infty}^{\infty}dx\,x\exp(-\frac{(x-x_0)^2}{b^2}).## ##y=x-x_0 \quad x=y+x_0 \quad dy=dx.## The boundaries remain infinite, I believe. ##\frac{1}{\sqrt{\pi b^2}}\int_{-\infty}^{\infty}dy(y+x_0)\exp(\frac{-y^2}{b^2}).## ##\frac{2}{\sqrt{\pi b^2}}\int_0^{\infty}dy\,y\exp(\frac{-y^2}{b^2})+\frac{2x_0}{\sqrt{\pi b^2}}\int_0^{\infty}dy\,\exp(-\frac{y^2}{b^2}).## I then resolved the two...
Hello everyone, I’m considering a point charge q that oscillates harmonically about the origin along the z-axis, e.g. $$z_{q}(t)= A\sin(wt)$$ In a strongly simplified / quasi-instantaneous approximation I ignore retardation and take the electric field at the position ##r=(x,y,z)## simply to be the “Coulomb field at the charge’s instantaneous position”: $$E(r,t)=\frac{q}{4\pi\varepsilon_{0}}\frac{r-r_{q}(t)}{||r-r_{q}(t)||^{3}}$$ with $$r_{q}(t)=(0,0,z_{q}(t))$$ (I’m aware this isn’t...
Hi, I had an exam and I completely messed up a problem. Especially one part which was necessary for the rest of the problem. Basically, I have a wormhole metric: $$(ds)^2 = -(dt)^2 + (dr)^2 + (r^2 + b^2)( (d\theta)^2 + sin^2 \theta (d\phi)^2 )$$ Where ##b=1## with an orbit only in the equatorial plane. We also know from the question that the orbit must satisfy this relationship: $$\varepsilon = \frac{1}{2} (\frac{dr}{d\tau})^2 + V_{eff}(r)$$ Ultimately, I was tasked to find the initial...
Back
Top