Finding eigenvalue energy between two spheres

Thread starter morteza65
Start date Jan 30, 2016
Tags

Eigenvalue Energy Spheres

AI Thread Summary

To find the eigenvalue and eigenfunction of energy spacing between two non-concentric spheres with radii a and b, and a center distance of d, one must consider the potential energy in the region between the spheres. The problem requires clarification on the physical context and boundary conditions, as the interaction between the spheres significantly influences the solution. A common approach involves solving the Schrödinger equation in the specified geometry, taking into account the boundary conditions at the surfaces of the spheres. The discussion highlights the need for a deeper understanding of the mathematical framework involved in quantum mechanics. Further insights into the specific potential energy configuration are necessary for a complete solution.

Jan 30, 2016

morteza65

Homework Statement

there are two spheres with radius a and b that b > a.they don't have the same center and the distance between their centers is d . how can I find eigenvalue and eigenfunction of energy spacing between two spheres... I don't have any idea. please help me .

Homework Equations

The Attempt at a Solution

Physics news on Phys.org

Jan 30, 2016

ChrisVer

Science Advisor

Is that a question? what is there between the spheres??

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...

View full post »

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...

View full post »

Thread 'Explain this asphalt sheen'

This problem is two parts. The first is to determine what effects are being provided by each of the elements - 1) the window panes; 2) the asphalt surface. My answer to that is The second part of the problem is exactly why you get this affect. And one more spoiler:

View full post »