Finding Forces & Work: 105 kg Mass Suspended by 7 m Rope

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To determine the horizontal force required to hold a 105 kg mail bag displaced 3 m from its initial position, the tension in the rope must be calculated, which is 1029 N. Using the angle of 25 degrees from the vertical, the horizontal force needed is found to be approximately 479 N. For the work done in moving the bag, the weight of the object multiplied by its displacement, adjusted for the angle, should be used. The calculations initially focused on the tension when the bag is hanging vertically, but need to account for the displacement. Correctly applying these principles will yield the necessary values for both force and work.
honeyspells
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::A mail bag with a mass of 105 kg is suspended by a vertical rope of length 7.00 m .

A) What horizontal force is necessary to hold the bag in a position displaced sideways a distance 3.00 m from its initial position?
Take free fall acceleration to be g = 9.80 m/s2 .

B) How much work is done by the worker in moving the bag to this position?
Take free fall acceleration to be g = 9.80 m/s2 .

m= 105 kg
y= 7 m
x= 3 m
So first I made a right triangle to find the angles, the angles I found were 25(from the vertical) and 66.

The tension in the string is 105 kg x 9.8 m/s2 right? with that I have T=1029 N

I then used 1029tan(25)= 479 N .What do I need to do to figure out ho much work is done?
tips for moving on?
 
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Work is the integral of the working force over the arc length through which it acts. Have you tried calculating that?
 
honeyspells said:
::A mail bag with a mass of 105 kg is suspended by a vertical rope of length 7.00 m .

A) What horizontal force is necessary to hold the bag in a position displaced sideways a distance 3.00 m from its initial position?
Take free fall acceleration to be g = 9.80 m/s2 .

B) How much work is done by the worker in moving the bag to this position?
Take free fall acceleration to be g = 9.80 m/s2 .

m= 105 kg
y= 7 m
x= 3 m
So first I made a right triangle to find the angles, the angles I found were 25(from the vertical) and 66.

The tension in the string is 105 kg x 9.8 m/s2 right? with that I have T=1029 N

I then used 1029tan(25)= 479 N .What do I need to do to figure out ho much work is done?
tips for moving on?
For work just take the weight of the object multiplied by its displacement, you'll probably need the angle you calculated above. Also, I think your above calculations are incorrect...
edit: not incorrect, just not what the problem is asking for
 
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you calculated the tension if the bag was just hanging vertically, I believe you need to calculate tension while the bag is displaced...
 
Ok, after doing this problem it looks like you are on the right track (you've calculated the weight and the angle to the vertical). Your next step will be to use the weight and angle to calculate the tension in the rope, then use this tension (and angle) to calculate the force needed to hold the bag a certain distance from the vertical.
 
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