Finding geodesics on a cone of infinite height

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SUMMARY

The discussion focuses on finding geodesics on a cone of infinite height defined by the equation x² + y² = tan²(α)z² using polar coordinates. The correct expression for z is clarified as z = r cot(α), and the user attempts to derive the differential elements dx, dy, and dz. The final goal is to integrate the expression for the line element ds, which is derived as ds = √((1 + cot²(α))dr² + r²dψ²), to find the Lagrangian L. The user also explores the application of Lagrange multipliers to verify the solution.

PREREQUISITES
  • Understanding of polar coordinates and their application in three-dimensional geometry.
  • Familiarity with calculus, particularly differentiation and integration techniques.
  • Knowledge of Lagrangian mechanics and the concept of geodesics.
  • Basic understanding of trigonometric functions, specifically cotangent and tangent.
NEXT STEPS
  • Study the derivation of geodesics in different coordinate systems, focusing on cylindrical coordinates.
  • Learn about Lagrange multipliers and their application in optimization problems in physics.
  • Explore the mathematical properties of cones and their geodesic paths.
  • Review integration techniques for solving differential equations related to physical systems.
USEFUL FOR

Students and researchers in mathematics and physics, particularly those studying differential geometry, calculus of variations, and classical mechanics.

Leb
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Homework Statement


Find the geodesics on a cone of infinite height, x^{2}+y^{2} = \tan{\alpha}^{2}z^{2} using polar coordinates (x,y,z)=(r\cos{\psi},r\sin{\psi},z) with z=r\tan(\alpha)
HW.png


The Attempt at a Solution



I am not sure with how should I expres the element dz^{2} ? When it is a function of α (My calculus was always weak especially stuff with creating a derivative by dividing...)

Thanks.
 
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Leb said:
with ##z=r\tan(\alpha)##
The question is wrong there. They mean ##z=r\cot(\alpha)##
α is a constant, r2 = x2+y2. You can obtain an expression for dz in terms of x, y, z, dx and dy. Does that help?
 
Thanks haruspex!

I just tried to write them down like this:

dx=\cos(\psi) dr - r\sin (\psi) d\psi
dy=\sin(\psi) dr + r\cos (\psi) d\psi
dz=\cot (\alpha) dr
and
ds = \sqrt{(1+\cot^{2}(\alpha))dr^{2}+r^{2}d\psi^{2}}
taking dr^{2} out of the square root and calling the constant term as k
ds = \sqrt{k+r^{2}\frac{d\psi^{2}}{dr^{2}}}dr And now to integrate with limits from zero to infinity ? (Does not matter since we are looking for L (Lagrangian), right ?)

Update
OK, so I think I have found a solution, r_{0}=const=r\cos(\frac{\psi + C}{\sqrt{k}}) I now should do it with lagrange multipliers. Will I get the same answer up to a constant ?
 
Last edited:

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