Finding Inverse Laplace Transforms with Residue Method

pooface
Messages
207
Reaction score
0

Homework Statement


Inverse laplace transforms

F(s)=\frac{5s-2}{s^{2}(s-1)(s+2)}


Homework Equations


Residue technique

The Attempt at a Solution



F(s)=\frac{5s-2}{s^{2}(s-1)(s+2)} = \frac{k1}{s^{2}} + \frac{k2}{s-1} + \frac{k3}{s+2}

I solved for K1,K2, and K3, which all came to be 1.

answer=e^{t}+e^{-2t}+t
textbook answer = e^{t}+e^{-2t}+t -2

Can someone explain to me how did the -2 come?
 
Last edited:
Physics news on Phys.org
It is very important that I know this. I was told that there was a k4 at the end but for problems we did in control theory class k4 was said to be 0 always and we took it as a rule.

So I need to know where this -2 came from.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top