In the figure, two particles, each with mass m = 0.79 kg, are fastened to each other, and to a rotation axis at O, by two thin rods, each with length d = 5.9 cm and mass M = 1.2 kg. The combination rotates around the rotation axis with angular speed ω = 0.32 rad/s. Measured about O, what is the combination's kinetic energy? I=Ʃmiri2 KE=1/2Iω2 (.79kg)(.059m2)+(.79kg)(.118m2) = .0137 = I 1/2(.0137)(.32rad/s2) = 7.01E-4 = KE Do I need to convert cm to m? Also how do you factor in the mass of the rod? I assume we need that, otherwise they wouldn't have given its mass, etc. I'm extremely new at all of this. Thank you!