Finding Kinetic Energy of An Alpha Particle

AI Thread Summary
To find the kinetic energy of an alpha particle emitted during the decay of Rn-220, the binding energy equation is used, where the initial energy equals the final energy. The binding energy of Rn-220 is equal to the sum of the binding energies of the alpha particle and Po-216, plus the kinetic energy of the alpha particle. The setup for the calculation appears to be correct, as the user can compute the binding energies for each particle involved. The discussion confirms the approach is valid and offers reassurance for the calculations. This method effectively determines the kinetic energy of the alpha particle in the decay process.
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Homework Statement



Problem: "Find the kinetic energy of an alpha emitted during the alpha decay of Rn-220. Assume that the daughter Po-216, has zero recoil velocity."

Homework Equations



Ei = Ef

The Attempt at a Solution



BE = Binding Energy, KE = Kinetic Energy

(BE of Rn-220) = (BE of Alpha) + (BE of Po-216) + (KE of Alpha)

I just want to know if I am setting it up correctly. I can easily calculate BE for each of the particles, so that's not a problem. Thanks in advance!
 
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Yes, that's correct.
 
Thanks.
 
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(Disclaimer: this is not a HW question. I am self-studying, and this felt like the type of question I've seen in this forum. If there is somewhere better for me to share this doubt, please let me know and I'll transfer it right away.) I am currently reviewing Chapter 7 of Introduction to QM by Griffiths. I have been stuck for an hour or so trying to understand the last paragraph of this proof (pls check the attached file). It claims that we can express Ψ_{γ}(0) as a linear combination of...
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