Finding Local Max/Min with f(x)= x + 9/x: Explained

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The discussion focuses on finding local maxima and minima for the function f(x) = x + 9/x. The user seeks clarification on how to express where the function is decreasing, questioning if the interval [-3,0)U(0,3] is correct due to the vertical asymptote at x=0. They calculate f(-3) and conclude that it results in a local minimum at the point (-3, -6). The conversation highlights the importance of understanding function behavior around asymptotes and critical points. Overall, the analysis leads to identifying local extrema effectively.
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ok so in the problem f(x)= x + 9/x, I know how to write where f is increasing, but how do you write how it's decreasing? Is it written as [-3,0)U(0,3]? since x=0 is a vertical asymptote wouldn't all the x-values between -3 and 3 be as close to 0 as possible?
 
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wouldnt f(-3) = -3 + 9 / (-3) = -3 -3 = -6
 
mathmike said:
wouldnt f(-3) = -3 + 9 / (-3) = -3 -3 = -6

yeah that's my local min at (-3,-6).
 
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