Finding magnetic flux-it's all worked, just have one question

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The discussion centers on calculating magnetic flux through a circular loop in a magnetic field. The loop has a diameter of 15 cm and is initially perpendicular to a 0.60-T magnetic field, yielding a flux of 1.1E-2 Wb. When the loop is rotated to a 36° angle with the field lines, the angle used in the flux equation is 55°. The user struggles with calculating the magnetic flux at this angle due to difficulty with trigonometric functions, specifically cosine. Assistance is requested for the correct calculation of the magnetic flux using the cosine of 55 degrees.
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Finding magnetic flux--it's all worked, just have one question

Homework Statement



A 15-cm-diameter circular loop of wire is placed in a 0.60-T magnetic field.
Enter scientific notation as 1.23E4.

When the plane of the loop is perpendicular to the field lines, what is the magnetic flux through the loop?


The plane of the loop is rotated until it makes a 36° angle with the field lines. What is the angle in Eq. 21-1 in your textbook, , for this situation?


What is the magnetic flux through the loop at this angle?


Homework Equations



\phiB=BA=B]\pir2

\phiB=BAcos\theta=B\pir2

The Attempt at a Solution



a. (.60T)*\pi*0.075m2=1.1E-2Wb

b. \theta=55 degrees

c. (0.60T)*\pi*0.075m2*cos55 degrees



I can get the 1st two questions correct, I know because it is online homework, but I can't get "c" right. It has been a while since I have had math with trig functions so I can't remember exactly how to calculate cosine. Can someone help me out.
 
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Do it with a calculator; cos(55 deg) = 0.5736.
 

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