Finding Maximum Current Entering A Terminal

[madhatter500]

Homework Statement

The expression for the charge entering an upper terminal of a component is:

q = 1/$\alpha^{2}$ - (t/$\alpha$ + 1/$\alpha^{2}$)e$^{-t\alpha}$

Find the maximum value of the current entering the terminal if $\alpha$ = 0.03679 s$^{-1}$

Homework Equations

The Attempt at a Solution

Since they gave us the equation for the charge, to find current we simply take the derivative with respect to time of the given equation. I did this and ended up with te$^{-t\alpha}$. This seems to check out just fine. I then realized that they want the maximum value that this derivative can be. So then I went ahead and took the second derivative and tried to set it equal to 0 (since that would be a local max or min). This ended up being very messy and it didn't work out. Is there an easier way to find the maximum current?

 

[MetalManuel]

Let me know if my mathematics is incorrect, but
$\frac{dq^{2}}{d^{2}t}=e^{-t\alpha}-\alpha te^{-t\alpha}=e^{-t\alpha}(1-\alpha t)=0$
$e^{-t\alpha}\neq0$, therefore $1-\alpha t=0$

and $t=\frac{1}{\alpha}$

You can go from there

edit: this is going from your 1st derivative, I haven't checked it myself

 

[PeterO]

Homework Statement

The expression for the charge entering an upper terminal of a component is:

q = 1/$\alpha^{2}$ - (t/$\alpha$ + 1/$\alpha^{2}$)e$^{-t\alpha}$

Find the maximum value of the current entering the terminal if $\alpha$ = 0.03679 s$^{-1}$

Homework Equations

The Attempt at a Solution

Since they gave us the equation for the charge, to find current we simply take the derivative with respect to time of the given equation. I did this and ended up with te$^{-t\alpha}$. This seems to check out just fine. I then realized that they want the maximum value that this derivative can be. So then I went ahead and took the second derivative and tried to set it equal to 0 (since that would be a local max or min). This ended up being very messy and it didn't work out. Is there an easier way to find the maximum current?

Not too comfortable with your first derivative. t appears in two places in the original expression. I think you may have overlooked one??

 

[madhatter500]

Let me know if my mathematics is incorrect, but
$\frac{dq^{2}}{d^{2}t}=e^{-t\alpha}-\alpha te^{-t\alpha}=e^{-t\alpha}(1-\alpha t)=0$
$e^{-t\alpha}\neq0$, therefore $1-\alpha t=0$

and $t=\frac{1}{\alpha}$

You can go from there

edit: this is going from your 1st derivative, I haven't checked it myself

Perfect. This gives me the correct answer. Looks like I need to brush up on my algebra! Thank you!

 

[rwisz]

Thank you for providing the equation and values for \alpha. To find the maximum value of the current entering the terminal, we need to first take the derivative of the charge equation with respect to time, which you have correctly done. However, to find the maximum value, we need to set the derivative equal to 0 and solve for t. This will give us the time at which the current is at a maximum. Plugging this value of t back into the derivative will give us the maximum current entering the terminal. There may be alternative methods to find the maximum current, but this is the most straightforward approach given the information provided.