Finding Maximum Velocity in Train Motion

AI Thread Summary
A train travels 1.2 km at an average velocity of 43.2 km/h, with distinct phases of acceleration, uniform motion, and deceleration. The total travel time is calculated to be approximately 97.2 seconds, allowing for the determination of the time spent in uniform motion. To find the maximum velocity, a velocity-time graph can be drawn, illustrating the train's acceleration, constant speed, and deceleration phases. The area under the velocity-time graph represents the distance traveled, which is crucial for solving the problem. Understanding these concepts is essential for accurately determining the maximum velocity of the train.
Vitalii
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Homework Statement


A train travels a distance of 1,2 km between two stations with an average velocity of 43.2 km/h. During it's motion, at the time t1=40s it moved accelerated, then at time t2 it moved uniformly, then at t3=40s it moved uniformly slowed. Find the maximum velocity of the train.
The acceleration during the slowed motion is equal in modulus to the acceleration during the accelerated motion.

distance=1,2 km
average velocity=43.2 km/h
t1=40s
t3=40s
|a3|= a1

Hopefully it makes sense.

Homework Equations



The Attempt at a Solution


I tried solving it by finding the total time. Ttotal=average velocity/total distance. 1.2/43.2=0.027 h or 97.2 seconds

from here i can find t2 which is 97.2-40-40=12.7
after this I'm stuck and don't know what to do next.
 
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Vitalii said:

Homework Statement


A train travels a distance of 1,2 km between two stations with an average velocity of 43.2 km/h. During it's motion, at the time t1=40s it moved accelerated, then at time t2 it moved uniformly, then at t3=40s it moved uniformly slowed. Find the maximum velocity of the train.
The acceleration during the slowed motion is equal in modulus to the acceleration during the accelerated motion.

distance=1,2 km
average velocity=43.2 km/h
t1=40s
t3=40s
|a3|= a1

Hopefully it makes sense.

Homework Equations



The Attempt at a Solution


I tried solving it by finding the total time. Ttotal=average velocity/total distance. 1.2/43.2=0.027 h or 97.2 seconds

from here i can find t2 which is 97.2-40-40=12.7
after this I'm stuck and don't know what to do next.

You could try drawing a graph of velocity against time.
 
PeroK said:
You could try drawing a graph of velocity against time.
How exactly can i draw a graph of velocity against time with all my known data?
 
Vitalii said:
How exactly can i draw a graph of velocity against time with all my known data?

What's the problem? It accelerates, it moves at constant speed for a time, then it decelerates to a stop. You can draw that.
 
PeroK said:
What's the problem? It accelerates, it moves at constant speed for a time, then it decelerates to a stop. You can draw that.
How do i draw a velocity against time graph?
 
Vitalii said:
How do i draw a velocity against time graph?

You put time along the x-axis and velocity along the y-axis, then you draw the velocity as a function of time.

You need to know that distance traveled is the area under the velocity-time graph.

Do they not teach you this anymore?
 
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