Finding mean values of a function

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SUMMARY

The mean value of the function (cos 2x)^7 over the interval 0 ≤ x ≤ 0.25π is calculated using the formula for the mean value of a function, which is defined as (1/(b - a)) * ∫_a^b f(x) dx. In this case, a = 0 and b = 0.25π. The integral required to solve this problem involves evaluating ∫_0^(0.25π) (cos 2x)^7 dx, which is essential for finding the mean value in terms of π.

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The question is :- Find the mean value of (cos 2x)7 with respect to x over the interval 0 ≤ x ≤ 0.25(pi), leaving your answer in terms of (pi).


I just don't know the formula for calculating this so if anyone call tell me that hopefully I will be able to solve this question by myself :)
 
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rdajunior95 said:
The question is :- Find the mean value of (cos 2x)7 with respect to x over the interval 0 ≤ x ≤ 0.25(pi), leaving your answer in terms of (pi).


I just don't know the formula for calculating this so if anyone call tell me that hopefully I will be able to solve this question by myself :)

The mean value of a function f over an interval [a, b] is defined as
[tex]\frac{1}{b - a}\int_a^b f(x) dx[/tex]

Since there's an integral involved, this should probably have been posted to the Calculus & Beyond section.
 
Thanks, I will try it out and see if I get the answer :)
 

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