In summary: You can solve for a by substituting one of the equations into the other and then solving for a. Once you have a, you can plug it back into either equation to solve for alpha.
The a will cancel out and what you wrote isn't correct. You either divide the first by the second and get [itex]\cot \alpha = - \sqrt 3 /3[/itex] or you divide the second by the first and you get what I had, which has the same solutions for alpha of course
#39
laker_gurl3
94
0
so what is the final answer? [itex]\tan \alpha = - \sqrt 3 [/itex]
and that's it?
Perhaps you should re-read all of the posts and think carefully, all the necessary information has been said. If something is still unclear, be specific about what the problem actually is.
#51
laker_gurl3
94
0
after all this 50 some post...look at the progression...