Finding Moment of Inertia of Cantilever Beam

AI Thread Summary
The discussion focuses on determining the moment of inertia (I) for a cantilever beam using the deflection equation d = PL^3 / 3EI. It clarifies that the problem involves manipulating the equation to isolate I, leading to the expression I = 1/d(PL^3/3E). The dimensions of I are confirmed to be [m^4], aligning with the definition of axial moment of inertia in mechanics of materials. The conversation emphasizes understanding the dimensional analysis related to the problem. Overall, the participants seek clarity on the relationship between deflection, force, and moment of inertia in this context.
EE_Student
Messages
2
Reaction score
0
Ok I was given this problem:

Problem: The deflection d of a cantilever beam of length L is given by the mechanics of materials equation d=PL^3/3EIWhere P is the force on the end of the beam and E is the modulus of elasticity, which has the same dimensions as pressure.Determine the dimensions of I which is the moment of Inertia.

Are they simply asking you to manipulate the equation for I? If so would the following be correct? A little help would be appreciated, thanks.

I= 1/d(PL^3/3E):confused:
 
Last edited:
Physics news on Phys.org
Any help appreciated.
 
is this a dimensional problem?, like stress is F/L^2, in a gravitational system (FLT)
 
Generally, we define the moment of inertia for a rigid body as \int_{V} r^2 \rho dV = \int_{V} r^2 dm, so the dimension is [kg*m^2]. But, in mechanics of materials, we define the axial moment of inertia of a cross section with the area A, as \int_{A} r^2 dA, where r is the perpendicular distance of the elementary area dA to the axis for which the moment of inertia is defined, so, for example, we have I_{z}=\int_{A} y^2 dA. So, the dimension is [m^4], which fits into your problem of expressing I out of d = PL^3 / 3EI.
 

Similar threads

Replies
2
Views
3K
Replies
5
Views
4K
Replies
8
Views
2K
Replies
1
Views
1K
Replies
14
Views
9K
Replies
8
Views
2K
Replies
17
Views
2K
Back
Top