Finding Momentum of a fragment after explosion

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The discussion revolves around calculating the momentum of fragment 2 after an explosion, given the momentum of fragment 1 as 23 kg·m/s at an angle of 28° RCS. Participants emphasize the importance of using conservation of momentum principles, breaking down the momentum into x and y components to solve for the unknown fragment. The conversation highlights the need to apply the equations for momentum and trigonometric functions to find the relationship between the fragments. There is a recognition that this problem differs from previous stationary object explosions encountered in class. Overall, the focus remains on applying conservation laws to determine the momentum of the second fragment.
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Homework Statement


A small explosive device slicing to the right breaks into two pieces. The momentum of fragment 1 after the explosion is 23kg.m/s 28°RCS

1Physics.jpg


What is the momentum of fragment 2 after the explosion?

Homework Equations


PT=PT'
P=mv
Rx= Rcos∅
Ry= Rsin∅
R= √x2+y2

The Attempt at a Solution


This is all the information given. I haven't a clue at how to even begin with this one. We generally receive minimal instruction, and we haven't done a single problem like this one. Everything else was a stationary object exploding and we were given masses and velocities and times.

Do I break it down into x and y components and find out the momentum of the grey line, then use that, combined with the 21° (331°?RCS(no clue if that's right, seeing as he went out in left field the other day with the rcs)) to get the momentum of fragment 2? That's the only thing I can think of
 
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Vertical component of momentm is also conserved.
Try to find the relation connecting sine components of the two pieces.
 
I was just about to ask what a feynman diagram was doing in introductory physics, then I read the question :D

it's all conservation of momentum!
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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