Finding Momentum with Uniform Magnetic Field: q, B, a, d

AI Thread Summary
A charged particle enters a uniform magnetic field, deflecting a distance d above its original path, indicating a positive charge based on the right-hand rule. The challenge lies in determining the momentum of the particle, as traditional equations for circular motion may not apply due to the lack of a defined radius in this scenario. The discussion highlights the need to formulate an equation for y displacement while incorporating x displacement to derive momentum. Participants express uncertainty about finding the correct approach, given that the particle's motion does not conform to typical cyclotron behavior. The conversation emphasizes the complexity of analyzing particle motion in a magnetic field without an electric field present.
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Homework Statement


A particle of charge q enters a region of uniform magnetic field B (pointing into the page). The field deflects a particle a distance d above the original line of flight. Is the charge positive or negative? In terms of a, d, B, and q, find the momentum of the particle.

x displacement is a
y displacement is d
particle is initially moving in the x direction

Homework Equations


p = QBR


The Attempt at a Solution


Charge is +q via the right hand rule with the magnetic field pointing into the page and force initially upward.

I'm just not sure how to find the radius. I tried finding a reference somewhere so if someone knows a good place to find the trig on this that would be great.
 
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That equation won't work in this situation (it applies to circular motion, e.g. in a cyclotron or something). Write out an equation for the y displacement... try to squeeze the x-displacement into it, then work that into momentum.
 
Isn't this situation a cyclotron except that there is no velocity in the direction along the magnetic fields axis (which is normally conserved) and there is no electric field so the particle is just spinning in a circle. My professor derived this equation with a similar problem so I'm pretty sure it is applicable.
 
Its the exact same conditions/setup... but the particle isn't moving in a circle. So there is no well-defined radius.
 
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