Finding normal force of moving crates

AI Thread Summary
The problem involves calculating the normal force between two crates being pushed along the floor at a constant velocity. The masses of the crates are 49 kg and 29 kg, with a coefficient of kinetic friction of 0.30. The frictional forces acting on each crate are determined using the equation Ff = μkFN, leading to the equations for each crate's normal force. By combining the frictional forces, the total normal force is found to be 23.4 kg, which is then divided equally between the two crates, resulting in a normal force of 11.7 kg for each crate. This analysis illustrates the relationship between mass, friction, and normal force in a system of moving objects.
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Homework Statement


Your moving company runs out of rope and hand trucks, so you are forced to push two crates along the floor as shown in the figure below. The crates are moving at constant velocity, their masses are m1 = 49 kg and m2 = 29 kg, and the coefficients of kinetic friction between both crates and the floor are 0.30. Find the normal force between the two crates.

Homework Equations


F = ma

The Attempt at a Solution



Ff = μkFN
 
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Ff1 = μk1FN1Ff2 = μk2FN2Ff1 + Ff2 = FN1 + FN2 (μk1m1) + (μk2m2) = FN1 + FN2 (0.30)(49 kg) + (0.30)(29 kg) = FN1 + FN214.7 kg + 8.7 kg = FN1 + FN2 23.4 kg = FN1 + FN2FN1 = 11.7 kgFN2 = 11.7 kg
 
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