Finding Product of z1z2 in Standard & Trig Forms

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SUMMARY

The discussion focuses on finding the product of two complex numbers, z1 = 1 + i and z2 = 4i, in both standard and trigonometric forms. The product in standard form is calculated as z1z2 = (1 + i)(4i) = 4i + 4i^2 = 4i - 4 = -4 + 4i. The trigonometric forms of z1 and z2 are derived as z1 = √2(cos(π/4) + i sin(π/4)) and z2 = 4(cos(π/2) + i sin(π/2)). The product in trigonometric form is then calculated and converted back to standard form, confirming the equality of both products.

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purplestar002
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Ok i am having a hard time with this one. Find the product z1z2 in standard form. Then write z1 and z2 in trig form and find their product again. Finally, convert the answer that is in trig form to standard form to show that the two products are equal.
z1= 1+i, z2= 4i
 
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Wow, this is a tough one! :rolleyes:

It's your homework, why not show us what you can do with it?
 

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