Finding Pure Bending Moment for Simply Supported Beam

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SUMMARY

The discussion focuses on calculating the pure bending moment for a simply supported solid beam measuring 3 meters in length, with a width of 100 mm and a depth of 200 mm. The beam is subjected to a uniformly distributed load (UDL) of 2 tonnes/m and a central point load of 200 N. The calculated reactions at the beam's ends are 29,530 N. The correct pure bending moment is determined by summing the maximum moments from both the UDL and the point load, which can be derived from standard formulas available online.

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  • Understanding of simply supported beam mechanics
  • Knowledge of bending moment diagrams
  • Familiarity with uniformly distributed loads (UDL)
  • Ability to apply static equilibrium equations
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  • Research the formulas for calculating bending moments for simply supported beams
  • Learn how to construct bending moment diagrams
  • Study the effects of point loads on beam reactions
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Structural engineers, civil engineering students, and anyone involved in beam analysis and design will benefit from this discussion.

andrewh21
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i am trying to find the pure bending moment of this beam

1. Homework Statement
simply supported solid beam 3m long W=100mm D=200mm with a UDL of 2tonnes/m and a point load in the centre of 200N

Homework Equations


is the pure bending moment at the peak of the bending moment diagram
i have calculated the reactions at the ends to be
29,530N
so 29,430*1.5/2=22,147 would this be the correct pure bending moment?
 
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Your reactions are correct. Your bending moment would be the sum of the maximum moments for the UDL and point load.
 
Thanks what is the formula for this?
 
I don't remember them off hand but they are readily available if you Google them. They're standard formulas based on the simple supports.
 

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