Finding Refraction Angle and Wavelength in Water for Sodium Light?

AI Thread Summary
To find the refraction angle and wavelength of sodium light in water, the index of refraction for water (n=1.33) is used alongside Snell's Law. The wavelength of sodium light in air (λ₀=5893 Å) can be calculated for water using the formula λ=λ₀/n. This results in a wavelength of approximately 4431 Å in water. The initial confusion arose from the application of the equations, but the correct approach was clarified. The calculations confirm that the wavelength in water is accurately derived.
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A narrow beam of sodium light (λ=5893 A) is incident from air on a smooth surface water at θ=35°. Find the refraction angle and wavelength in water.

n=λ_0/λ:wavelength of light in a material
n_asinΘ_a=n_bsinΘ_b: snells law
n=c/v:index of refraction

I tried using the wavelength of light in a material to find n. I got confused because λ will equal each other. I am not sure if it is correct. Please help. Thanks
 
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You need to look up what n is for water, then apply the equation to find the wavelength in water.
 
n=λ_0/λ
λ=λ_0/n, water n=1.33, and λ_0=5893
λ=5893/1.33= 4431 A Is this correct?
 
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