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Finding slope of tangetns

  1. Apr 14, 2008 #1
    Find the slope of the tangent to the parabola y=-3x^2 + 4x - 7 when x=a. I know how to get the limit using the tangent so i end up with a slope in terms of a (you can also get it using the derivative) but now the next part states:
    At what point on the parabola is the tangent perpendicular to the line 3x - 4y + 8=0 and all that i get from that question is that the tangent for the point on the parabola will have a slope of -4/3 (negative reciprocal)
    Last edited: Apr 14, 2008
  2. jcsd
  3. Apr 14, 2008 #2
    so you have the derivative in terms of a, right? Let's call it D(a).

    You're looking for the value for a such that this expression is equal to -4/3.

    So what about solving D(a)=-4/3 for a ..?
  4. Apr 14, 2008 #3
    sorry... so if the derivative is 6x + 4, then i can say that 6x + 4= -4/3 and solve for a (or x)?
  5. Apr 14, 2008 #4
    Exactly, sometimes it's easier than you think :smile:
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