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Finding slope of tangetns

  • Thread starter emma3001
  • Start date
42
0
Find the slope of the tangent to the parabola y=-3x^2 + 4x - 7 when x=a. I know how to get the limit using the tangent so i end up with a slope in terms of a (you can also get it using the derivative) but now the next part states:
At what point on the parabola is the tangent perpendicular to the line 3x - 4y + 8=0 and all that i get from that question is that the tangent for the point on the parabola will have a slope of -4/3 (negative reciprocal)
 
Last edited:

Answers and Replies

so you have the derivative in terms of a, right? Let's call it D(a).

You're looking for the value for a such that this expression is equal to -4/3.

So what about solving D(a)=-4/3 for a ..?
 
42
0
sorry... so if the derivative is 6x + 4, then i can say that 6x + 4= -4/3 and solve for a (or x)?
 
Exactly, sometimes it's easier than you think :smile:
 

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