Finding Solution Set for Vectors

  • Thread starter Thread starter symsane
  • Start date Start date
  • Tags Tags
    Set
symsane
Messages
13
Reaction score
0
How can I determine the solution set?

(1+2i)x1 + (1-i)x2 + x3 = 0,
ix1 + (1+i)x2 - ix3 = 0,
2ix1 + ix2 + (1+3i)x3 = 0.

Thanks..
 
Physics news on Phys.org
Simply perform row-reduction to reduce the system to its row echelon form. The only difference with this and matrices containing only real numbers is that you can now multiply row by complex numbers as well.
 
Or just solve the three equations the way you learned to solve linear equations way back. For example, subtracting 2 times the second equation from the third eliminates x1.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
Back
Top