symsane
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How can I determine the solution set?
(1+2i)x1 + (1-i)x2 + x3 = 0,
ix1 + (1+i)x2 - ix3 = 0,
2ix1 + ix2 + (1+3i)x3 = 0.
Thanks..
(1+2i)x1 + (1-i)x2 + x3 = 0,
ix1 + (1+i)x2 - ix3 = 0,
2ix1 + ix2 + (1+3i)x3 = 0.
Thanks..