Finding spring constant in elevator

AI Thread Summary
In a scenario where a 2000-kg elevator falls at 25 m/s before contacting a spring, the goal is to determine the spring constant needed to safely stop the elevator. The relevant energy considerations include the initial kinetic energy (KE) and gravitational potential energy (GPE), with a frictional force of 17,000 N acting against the motion. The work done by the friction force and the energy stored in the spring must be balanced to find the spring constant. The discussion clarifies that the energy calculations should focus on the moment the elevator first contacts the spring, where the height for GPE is 3m, and the friction acts over this same distance. The key takeaway is that the spring constant can be derived from the energy equations once the correct parameters are established.
Maiia
Messages
78
Reaction score
0

Homework Statement


In a 'worst-case' design scenario a 2000-kg elevator with broken cables is falling at 25m/s when it first contacts a cushioning spring at the bottom of the shaft. The spring is supposed to stop the elevator, compressing 3m as it does so. During the motion, a safety clamp applies a constant 17,000N frictional force to the elevator. As an energy consultant, you are asked to determine what the force constant of the spring should be.

The Attempt at a Solution


The way I set up the problem was like this:

Work done by noncons force + GPE initial+ KE initial+ EPE initial= GPE final + KE final+ EPE final
EPE initial is 0. I set my zero as the point when the mass is coming to rest on the spring for a slight instant before compressing the spring. I assume the 25m/s is a constant velocity...? If so, then KE inital and KE final cancel. So I am left with:
-fd + mgy0= mgyf + .5kx^2
thing is, then I have two unknowns, because I don't know the spring constant and I don't know what height it starts off at...If someone could point me in the right direction, I would greatly appreciate it:)
 
Physics news on Phys.org
No, 25 m/s is not constant. It was 25 m/s at the point where the elevator first contacts the spring, then, at full compression, the speed is zero.

The energy going into the problem is KE+GPE. The height for GPE is the 3m it will compress.

The dissipated energy is-Fd, ans you noted, where d is the same 3m. The remaining energy is in the spring.
 
Why is d 3m for -Fd? I thought the d would be the entire distance the elevator was falling? Because isn't Work done the total distance over which the friction acts?
 
in the same vein, why would the h for the GPE be 3m as well? assuming that this is the initial GPE, wouldn't h be the height at which the elevator starts falling at? How do we know it starts at a height of 3m?
 
Your equation should reflect both terms.

KE of the initial 1/2mv² = 1/2kx² + 17000 * x

Looks like everything is known but the spring constant k, which happily is what they asked you to find.
 
Last edited:
Maiia said:
Why is d 3m for -Fd? I thought the d would be the entire distance the elevator was falling? Because isn't Work done the total distance over which the friction acts?

The problem "starts" at the moment the elevator contacts the spring. At this point it is moving at 25 m/s. The energy of the system is assessed at this moment. Whatever happened before is irrelevant. At this moment, it has KE (due to 25 m/s) and GPE (due to 3m above final position).
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top