Finding Squares Between Cubes in Elementary Number Theory

tara123
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Im really good at number theory but how to show this statement has me stumped!

"Show that among the positive integers greater than or equal to 8, between any two cubes there are at least 2 squares"
 
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Can you find 2 squares between n^3 and (n+1)^3?
 
yah if u allow for the restriction of n>=8
if u have 8^3=512 and 9^3=729
then there's 23^2=529 and 24^2=576 both of which are between the cubes..
 
You have found two squares between the two particular cubes 8^3 and 9^3, but what about between two generic cubes n^3 and (n+1)^3, where n is arbitrary (and >1).

You can do it by showing it is not possible to have two cubes between m^2 and (m+2)^2. That is, assume m^2 < n^3 and (n+1)^3 < (m+2)^2 and deduce a contradiction.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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