Finding stress energy tensor of a rod under tension

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SUMMARY

The stress energy tensor for a rod under uniform tension is defined with specific values based on its physical properties. For a rod with mass per unit length \(\mu\) and cross-sectional area \(A\), the energy density is given by \(T^{00} = \mu / A\). The momentum density and energy flux components \(T^{0i}\) and \(T^{i0}\) are zero due to the rod being stationary. The only non-zero entry in the momentum flux tensor is \(T^{11} = F/A\), where \(F\) is the uniform tension acting along the rod's length.

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  • Understanding of stress energy tensor components in physics
  • Knowledge of uniform tension and its effects on materials
  • Familiarity with mass per unit length and cross-sectional area concepts
  • Basic principles of momentum density and flux in continuum mechanics
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  • Study the derivation of the stress energy tensor in general relativity
  • Explore applications of stress energy tensors in different physical systems
  • Learn about the implications of non-zero momentum density in dynamic systems
  • Investigate the effects of varying cross-sectional areas on stress distributions
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Physicists, engineers, and students studying continuum mechanics or general relativity, particularly those interested in the behavior of materials under tension.

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I am given a rod with mass per unit length \mu, cross sectional area A, and under a tension F. I am also told that the tension F is uniform over the cross sectional area A. Find the stress energy tensor inside the rod.

I know that for the stress energy tensor T^{00} gives the energy density, T^{0i} gives the energy flux through a i-surface, T^{i0} gives the i-momentum density, and T^{ij} gives the i-momentum flux through a j-surface.

I have that T^{00} = \mu / A and that T^{0i} = T^{i0} = 0 since the rod is stationary so the particles have no net momentum. As for T^{ij}, if i assume that the rod is lying lengthwise along the x axis, then T^{11} = F/A since the momentum flux is the momentum per unit time per unit area or in other words the force per unit area. Then it seems to me that T^{ij} = 0 for all other entries since the tension acts along the x direction.

Therefore the stress energy tensor only has 2 nonzero entries on the main diagonal, and the rest of the entries are 0. Am I missing something here? It seems too simple a form to have and I am not sure if i took everything into account.
 
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The stress energy tensor inside the rod is: T^{00} = \mu / A T^{ij} = 0 (for all i,j except for i = j = 1)T^{11} = F/A
 

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