Finding the Angle of Motion After an Impulse

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In this discussion, a particle A with a mass of 3kg is connected to particles B and C, with masses of 5kg and 1kg, respectively, and is subject to an impulse directed away from B and C. The problem requires demonstrating that A moves at an angle alpha relative to the impulse direction, defined by the equation tan(alpha) = 2 sin(theta)/(6 - 3cos(theta)). Key considerations include the direction of velocities for particles B and C post-impulse, the constraints relating the velocities of A with B and C, and the total linear momentum of the system after the impulse. Understanding these relationships is crucial for solving the problem accurately. The discussion emphasizes the importance of analyzing momentum components and constraints in multi-body systems.
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Homework Statement


A particle A, of mass 3kg, is connected by light, inextensible strings to particles B and C, of masses 5kg and 1kg respectively. They lie at rest on a smooth horizontal plane, with the strings just taut and angle BAC=theta. A then receives and impulse directed away from B and C along the bisector of the angle BAC.Show that A starts to move at an angle alpha to the direction of the impulse, where

tan (alpha) = 2 sin (theta)/6-3cos(theta)

Please provide detailed explanations along with your answer, thanks in advance! :D


Homework Equations





The Attempt at a Solution


Sorry I don't even know where to start! Please help me with this question, thanks in advance! :)
 
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Oh goodie, another stringy problem :-p. Ok, some things to consider:

1. What is the direction of the velocity of B after the impulse? of C?
2. There is an important constraint condition relating the velocity of A and the velocity of B after the impulse. What is it? Can you express it mathematically? Similarly for A and C.
3. What can you say about the total linear momentum of the system after the impulse? In particular, what is the value of the component of the total momentum in a direction that’s perpendicular to the impulse?
 
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