Finding the angular momentum using the inertia tensor/matrix

Click For Summary
The discussion focuses on calculating the angular momentum of a thin ring with a non-uniform linear mass density, specifically addressing two methods: using the inertia tensor and direct integration. Participants emphasize the importance of incorporating the variable density function, ρ(θ) = ρ0(2 + sin²θ), when calculating the moment of inertia. There are questions regarding the correct limits for integration and the appropriate coordinate system to use, with some confusion about mixing Cartesian and polar coordinates. Clarifications are sought on whether to integrate with respect to multiple variables or just one. Accurate integration and consideration of the density function are crucial for solving the problem correctly.
shanepitts
Messages
84
Reaction score
1

Homework Statement


A thin ring of radius r is constrained to rotate with constant angular velocity ω as shown in attached picture. Let the linear mass density of the ring be ρ(θ)=ρ0(2+sin2θ) where ρ0 is constant.

a) Find the angular momentum L of the ring about O, at the instant the ring is in the xy plane as shown. Answer this part twice: (i) by using the moments and products of inertia Iij, and (ii) by directly integrating L=∫dmr x v.
image.jpeg


Homework Equations


The moment of inertia tensor/ matrix.
L==ntransposeIn

The Attempt at a Solution


Not sure if I am starting this problem properly, attached below is my attempt.
image.jpeg


Knowing that I must plug these moments and products of India inside the tensor matrix.

Please help
 
Physics news on Phys.org
When you calculated the moment of inertia Ixx, you treated the density of the ring, ρ, as a constant. According to the OP, ρ(θ) = ρo(2+sin2θ), where ρo is a constant. If you are going to calculate the MOI matrix for the ring, you must take this arbitrary density function into account. This extends even to calculating the mass of the ring.
 
  • Like
Likes shanepitts
SteamKing said:
When you calculated the moment of inertia Ixx, you treated the density of the ring, ρ, as a constant. According to the OP, ρ(θ) = ρo(2+sin2θ), where ρo is a constant. If you are going to calculate the MOI matrix for the ring, you must take this arbitrary density function into account. This extends even to calculating the mass of the ring.

Thank you.

But are my integral limits correct considering it is a ring? Moreover, shall I integrate with respect to y, x, and/or θ, or just one variable?
 
shanepitts said:
Thank you.

But are my integral limits correct considering it is a ring? Moreover, shall I integrate with respect to y, x, and/or θ, or just one variable?
I don't think so.

You seem to have integrands which use cartesian coordinates while the limits appear to be expressed in polar coordinates (what does x = 2πr mean? Isn't that the circumference of the ring?)
 
  • Like
Likes shanepitts
SteamKing said:
I don't think so.

You seem to have integrands which use cartesian coordinates while the limits appear to be expressed in polar coordinates (what does x = 2πr mean? Isn't that the circumference of the ring?)

Thanks.
 

Similar threads

  • · Replies 19 ·
Replies
19
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
Replies
5
Views
2K
  • · Replies 17 ·
Replies
17
Views
854
  • · Replies 4 ·
Replies
4
Views
3K
Replies
5
Views
2K
Replies
3
Views
2K
Replies
4
Views
3K
  • · Replies 3 ·
Replies
3
Views
4K
  • · Replies 45 ·
2
Replies
45
Views
4K