Finding the angular spread of a diffraction minima?

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To find the angular spread of the first diffraction minima for a single slit illuminated by light of wavelength 6000Å, the relevant equations include Y = nλ/a for minima and Y = (2n±1)λ/a for maxima. The discussion highlights confusion regarding whether the angular spread of a minima is determined by the angles subtended by the adjacent maxima. It notes that the width of the diffraction minima is often overlooked in problems, leading to ambiguity in the calculations. The thread suggests seeking clarification from an instructor for a more precise understanding. Overall, the topic emphasizes the complexity of calculating angular spreads in diffraction patterns.
Peter Andrews
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1. Homework Statement
Light of wavelength 6000Å illuminates a single slit of width 10-4m. Calculate the angular spread of first diffraction minima.

Homework Equations


d*y/D = nλ
Y = nλ/a for minima
Y = (2n±1)λ/a for maxima
Y stands for the position on screen, d is slit width and D is separation between screen and slit.

The Attempt at a Solution


I understand that the angular spread of any maxima is the difference in the angles subtended by the two minima on either side of it. But what about angular spread of a minima? Is it the difference in the angles subtended by the two maxima on its either side?
 
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Normally the width of the diffraction minima is a problem that is not addressed because there doesn't seem to be a precise answer to the question. Perhaps your instructor can provide further clarification.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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