ILoveBaseball
- 30
- 0
If f(\theta) is given by:f(\theta) = 6cos^3(\theta) and g(\theta) is given by:g(\theta) = 6sin^3(\theta)
Find the total length of the astroid described by f(\theta) and g(\theta).
(The astroid is the curve swept out by (f(\theta),g(\theta)) as \theta ranges from 0 to 2pi )
f/d(\theta) = -18*cos(x)^2*sin(x)
g/d(\theta) = 18*sin(x)^2*cos(x)
this is asking for arclength right?
my integral:
\int_{0}^{2\pi}\sqrt{(-18*cos(\theta)^2*sin(\theta))^2+(18*sin(\theta)^2*cos(\theta))^2}
anyone what's wrong with my integral? cause i keep getting the wrong answer.
Find the total length of the astroid described by f(\theta) and g(\theta).
(The astroid is the curve swept out by (f(\theta),g(\theta)) as \theta ranges from 0 to 2pi )
f/d(\theta) = -18*cos(x)^2*sin(x)
g/d(\theta) = 18*sin(x)^2*cos(x)
this is asking for arclength right?
my integral:
\int_{0}^{2\pi}\sqrt{(-18*cos(\theta)^2*sin(\theta))^2+(18*sin(\theta)^2*cos(\theta))^2}
anyone what's wrong with my integral? cause i keep getting the wrong answer.
Last edited: