Finding the area of an oil slick

  • Thread starter Thread starter iamjohnny56
  • Start date Start date
  • Tags Tags
    Area Oil
AI Thread Summary
To find the area of an oil slick formed by 1.56 m^3 of oil, each molecule occupies a cube of 0.792 nm on a side, which converts to 7.92E-10 m. The initial calculation yielded an area of approximately 1.97E9 m^2, but it was incorrect due to a formatting error when entering the exponent in the uTexas system. The user acknowledged their dyslexia contributed to the mistake and expressed gratitude for the assistance in identifying the issue. The discussion highlights the importance of careful attention to detail in calculations and input formats.
iamjohnny56
Messages
10
Reaction score
0

Homework Statement



Assume that an oil slick consists of a single layer of molecules and that each molecule occupies a cube 0.792 nm on a side.
Determine the area of an oil slick formed by 1.56 m^3 of oil.
Answer in units of m^2.

Homework Equations



1 nanometer = 1.0E9 meters

The Attempt at a Solution



.792 nm = 7.92E-10 m

(1.56 m^3) / (7.92E-10 m) = 1.97E9 m^2

---

I think I'm doing everything right, but it's coming up as wrong...could someone please look through my work and point out anything I'm doing wrong?

That would be much appreciated, thanks!
 
Physics news on Phys.org
If you imagine the volume of oil as a cube consisting of a stack of many one-molecule-thick layers, then what you have calculated is the area of a single layer.
 
Thanks, lewando. I realized that I forgot the "+9" after the E when entering the problem in uTexas...although that's never been an issue before, I guess uTexas now requires that for exponents.
 
I'm glad it you figured that out. Please disregard my prior post altogether. I am flat-out dyslexic and it resulted in me giving you bad information.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top