Find the Volume of an Oil Deposit

  • Thread starter Thread starter nzashadow
  • Start date Start date
  • Tags Tags
    Oil Volume
Click For Summary
SUMMARY

The discussion focuses on estimating the volume of an oil deposit located 2000 meters below the surface, using gravitational measurements. The gravity at the location is 5 parts in 10^7 smaller than average, with rock density at 3000 kg/m³ and oil density at 800 kg/m³. The approach involves applying the Universal Law of Gravity and considering the oil deposit as a spherical mass with negative density relative to the surrounding rock. The key equation discussed is g = F/m, where gravitational force is derived from the differences in density between the oil and the surrounding earth.

PREREQUISITES
  • Understanding of gravitational force and density concepts
  • Familiarity with the Universal Law of Gravity
  • Knowledge of spherical volume calculations
  • Basic physics equations related to mass and gravity
NEXT STEPS
  • Study the application of the Universal Law of Gravity in geophysical contexts
  • Learn how to calculate the volume of a sphere and apply it to real-world scenarios
  • Explore the concept of negative density and its implications in geophysics
  • Investigate methods for measuring gravitational anomalies in oil exploration
USEFUL FOR

Geologists, physics students, and professionals involved in oil exploration and geophysical analysis will benefit from this discussion.

nzashadow
Messages
10
Reaction score
0

Homework Statement



A geologist searching for oil finds that the gravity at a certain location is 5 parts in 10^7 smaller than average. Assume that a deposit of oil is located 2000 meters directly below.

Estimate the size of the deposit, assumed spherical. Take the density (mass per unit volume) of rock to be 3000 kg/m^3 and that of oil to be 800 kg/m^3.

Homework Equations



g = F/m ...?

The Attempt at a Solution



Usually when trying to do physics homework, I try to build the solution without following the book, or looking up equations, based on my understanding of how the concepts work out.

My first thought was to find the radius of the oil deposit... however I could see no way to figure that out. My second thought, and my first approach, was to cube the distance, and turn it into a ratio problem. However several attempts an reattempts just did not seem to work. After a long while I did consult the book, which had no examples that I could see related to the problem.

I did find one equation that seems like it could be applied to the situation, however I cannot seem to figure out how to apply it. This equation being g = F/m.
 
Physics news on Phys.org
Use the Universal law of gravity, F=GmM/r2, the force between two point masses m and M at distance r. A homogeneous sphere can be considered as a point mass in the centre of the sphere. The Earth can be considered so, but it has the oil deposit with less density than that of the Earth. You can handle the problem that you have the Earth, and the oil deposit, an other sphere, with centre 2000 m from the surface, where the material of the Earth is missing, and is filled with a lower density material, so having negative density: ρ=ρ(oil)-ρ(earth). The resultant of the gravitational forces of both spheres on unit mass is the gravitational force measured. So the difference from the average gravity is equal to the gravity of a sphere with density ρ=ρ(oil)-ρ(earth).

ehild
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 17 ·
Replies
17
Views
3K
  • · Replies 52 ·
2
Replies
52
Views
5K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 4 ·
Replies
4
Views
5K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 21 ·
Replies
21
Views
21K
  • · Replies 10 ·
Replies
10
Views
3K
  • · Replies 2 ·
Replies
2
Views
4K