Thanks I think the problem is solvable,. I want to be sure I'm on the right track
First, the magnet is in a small air pocket, then comes the steel/iron which has the coil in it. I exaggerated the diagram.
Second, it will be only the magnet moving vertically up and down with a defined velocity equation just like in how induction works but instead of coil of wire surround the magnet it will be in a circular rod shaped all tightly winded up together.
[PLAIN]http://img841.imageshack.us/img841/1220/finaldiagram.png
The brown is the coil of wire going around the two magnets which will be stationary
The gray region represent the steel or iron, haven't decided which one, probably going to go with iron
the light blue region represent air
So coming back to the equations, let's say the magnet moves up,
[PLAIN]http://img607.imageshack.us/img607/6446/changeinflux2.jpg
Lets say the cross section area of wire from the front view is the yellow region, the flux density region created by the magnet is the red region. Initially the coil of wire lies in the region of the flux but when the magnet moves up, the flux region too moves up producing change in flux region in the coil of wire. I kept the flux perpendicular to the motion of the magnet and assumed if the magnet moves up, the flux region also moves up instead of creating a new flux which will be lower in strength which would still exist, I said, it will not exist..
Coming back to equation, the magnet is rectangle, the magnets are close together too.
- I will calculate the [PLAIN]https://www.physicsforums.com/latex_images/33/3302875-2.pngusing the equation from the link by simply plug n chuging the numbers
- Next I will find the flux area [PLAIN]https://www.physicsforums.com/latex_images/33/3302875-3.png changing at intervals, time:1,2,3,4 ... the veocity motion is periodic and magnet will come down. I will plot it and find the equation of flux change w.r.t. So the area will change with velocity of the magnet moving up, the faster it moves up, the more flux change there will be in one second, the more current will be induced.
- Now I have B and area change w.r.t, I will be able to find voltage induced [PLAIN]https://www.physicsforums.com/latex_images/33/3302875-4.png
- I'm going to assume the air pocket to be very samll so the affect will be negilible but practically, the air gap is noticeable and I KNOW it will affect the results.
Again, the coil are OUTSIDE the magnets, not in between or anything, they are bascially OUTSIDE magnet casing - surrouding it and its the magnet which will be moving, not the coils.
I hope I got it right... because if I did, I'm of to paper and pencil and solving it. It good I have all the equations now
But Now i have to do,
use the velocity equation and relate it somehow to the changing area. Because the velocity is vertically up and the for example the velocity equation is y=2x. Y=2x represent the length. dy/dt=dl/dt. So the area is simple dydt*w [width of the rectangle which is OUTSIDE covering the cross section of the wire].
The only confusion I'm facing right now is DO I us the radius of coil of wire to find the total voltage induced? The radius was used before find the B on the square region which was R distance way. And I know the induced is flux over change which I found but shouldn't I be using the circumference somewhere to find the TOTAL induced voltage in the coil instead of find it on the cross section? Maybe [PLAIN]https://www.physicsforums.com/latex_images/33/3302875-4.png * {2piR}? Or it isn't necessary? Like i want total induced voltage.