- #1

- 2

- 0

I've been using F=ma so 1.5(.12)=.18N

the weight pulling is equal to .05kg(9.8)=.49N

.49-.18=.31N=Ff Ff=m(Fn) .31=m(1500) m (the coefficient of friction)= .0002

I dont feel like this is the right answer, can anyone see what I'm doing wrong?

- Thread starter BlakcDahlia
- Start date

- #1

- 2

- 0

I've been using F=ma so 1.5(.12)=.18N

the weight pulling is equal to .05kg(9.8)=.49N

.49-.18=.31N=Ff Ff=m(Fn) .31=m(1500) m (the coefficient of friction)= .0002

I dont feel like this is the right answer, can anyone see what I'm doing wrong?

- #2

- 10

- 0

Check your calculation for the normal force...Where did you get 1500 from?

- #3

- 2

- 0

I thought in Normal force was measured in grams, not kilograms. That may be where I went wrong. So the proper equation should be .31/1.5=.2? That seems pretty simple and for some reason feel like I've messed up somewhere else but if that's all that I seem to have done wrong then thanks!Check your calculation for the normal force...Where did you get 1500 from?

- #4

- 10

- 0

- #5

- 12,102

- 130

Forces are measured in Newtons. Grams and kilograms are used for mass, not force.I thought in Normal force was measured in grams, not kilograms.

- Last Post

- Replies
- 15

- Views
- 3K

- Last Post

- Replies
- 2

- Views
- 2K

- Last Post

- Replies
- 7

- Views
- 1K

- Last Post

- Replies
- 1

- Views
- 981

- Last Post

- Replies
- 1

- Views
- 840

- Last Post

- Replies
- 11

- Views
- 1K

- Last Post

- Replies
- 6

- Views
- 2K

- Last Post

- Replies
- 2

- Views
- 11K

- Last Post

- Replies
- 5

- Views
- 966

- Last Post

- Replies
- 1

- Views
- 797