# Finding the Coefficiant of friction

A cart that weighs 1.5 kg is accelerating at .12 M/s^2 on a horizontal surface. The cart is being pulled by a weight of 50 grams. Find the coefficiant of friction.

I've been using F=ma so 1.5(.12)=.18N

the weight pulling is equal to .05kg(9.8)=.49N

.49-.18=.31N=Ff Ff=m(Fn) .31=m(1500) m (the coefficient of friction)= .0002

I dont feel like this is the right answer, can anyone see what I'm doing wrong?

Related Introductory Physics Homework Help News on Phys.org
Check your calculation for the normal force...Where did you get 1500 from?

Check your calculation for the normal force...Where did you get 1500 from?
I thought in Normal force was measured in grams, not kilograms. That may be where I went wrong. So the proper equation should be .31/1.5=.2? That seems pretty simple and for some reason feel like I've messed up somewhere else but if that's all that I seem to have done wrong then thanks!

Again make sure all your calculations are correct...If the Ff = .31 N and the mass of the object is 1.5 kg use the equation µmg=Ff to solve for µ. I think you understand the concepts, just make sure you are doing the algebra correctly...

Redbelly98
Staff Emeritus