Finding the coefficients of a Resistance vs. Temp curve

AI Thread Summary
To find the coefficients Ro, a, and b for a Resistance vs. Temperature curve, the problem requires measurements at the ice, steam, and sulfur points. The initial calculation shows Ro equals 7 ohms at 0°C, leading to a system of equations for the other two temperatures. The challenge arises because the coefficients for a and b are not easily cancelable, complicating the solution process. After some confusion, the user resolves the issue, noting that their linear algebra course did not cover such scenarios. The discussion highlights the differences in problem-solving approaches between mathematicians and physicists.
guyvsdcsniper
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Homework Statement
Find Ro, a, and b.
Relevant Equations
R(T) = Ro (1 + aT + bT2 )
I am asked to find Ro, a, and b. Th problem states the values are determined by the measurements at the normal ice, steam and sulfur points. So I approached the problem by plugging the the temperature problems. For 0°C, Ro reduces to 7 ohms. Then for the other two non zero temperatures, it looks like I am left with a system of equations.

I am a bit stumbled because the values associated for a and b of both equations arent factors of each other, so canceling out seems a bit trickier. I don't really recall running across a problem like this before.

Am I approaching this problem correctly? If so what is a way to solve for a and b?
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You have three temperatures which means that you can write three equations, one at each temperature, and three unknowns. The first equation gives you (as you have already found) R0 = 7 Ω. Use that value in the other two equations which form a system of 2 equations and 2 unknowns a and b. Can you solve that?
 
kuruman said:
You have three temperatures which means that you can write three equations, one at each temperature, and three unknowns. The first equation gives you (as you have already found) R0 = 7 Ω. Use that value in the other two equations which form a system of 2 equations and 2 unknowns a and b. Can you solve that?
I figured it out. I actually just finished a linear algebra course and they never gave us a problem like that where the coefficients weren't perfect factors of each other.

Very noob post. Sorry lol
 
quittingthecult said:
I figured it out. I actually just finished a linear algebra course and they never gave us a problem like that where the coefficients weren't perfect factors of each other.
Yes, but don't berate yourself. You were led up the garden path. Mathematicians sometimes have a different view of the world from physicists.
 
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