Finding the Critical Velocity for Special Relativity Effects

AI Thread Summary
To find the velocity (v) at which Gamma (G) equals 1.0100, the correct formula for Gamma is essential, which is expressed as γ = (1 / √(1 - v²/c²)). The discussion highlights a common confusion regarding the exponent in the formula, clarifying that it should be 1/2 rather than 2. Participants suggest simplifying the equation by squaring both sides to isolate v. Ultimately, the conversation emphasizes the importance of correctly applying the definitions and equations in special relativity to solve the problem effectively.
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Homework Statement


For what value of v does Gamma (G) =1.0100? Observe that for speeds lower than this value, time dilationand length contraction are effects amounting to less that 1%


Homework Equations


L=Lp/G=Lp(1-(v^2/c^2))^2


The Attempt at a Solution


I do not know where to start. Is this the correct formula, and then if it is, how would I go about solving for the Velocity?
 
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You seem to have the wrong expression for gamma, unless it's a typo.
 
The exponent on the right should be 1/2 (square root), not 2. Start with

\frac{L_p}{\gamma} = L_p \sqrt{1 - v^2 / c^2}

What can you do to simplify this equation a bit, first?
 
Why involve any lengths here? You have an equation (rather a definition) for Gamma do you not? Isn't it just

\gamma=\left( \frac{1}{1-\frac{v^2}{c^2}} \right)^{\frac{1}{2}}

If so, try squaring both sides of the equation.
 
I got it! Thank you!
 
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