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Finding the current through a resistor using superposition theorem.

  • Thread starter Pottymouth
  • Start date
  • #1

Homework Statement


We have this circuit.
P1cLu.png


The problem states to find i, or the current through the 3 ohm resistor.

Homework Equations


V = IR


The Attempt at a Solution



I've started by shorting out both voltage sources and leaving only the current source in the circuit. I paralleled the 4ohm resistor and the 3ohm resistor nearest the current source to get 12/7 ohms equivalent resistance. Multiplying that by 3A gives me 5.1 volts going through the 4 ohm resistor nearest the current source and 5.1 volts going through the 3 ohm resistor.

Dividing 5.1 volts by 3ohms gives me 1.7A going through the 3 ohm resistor from the current source alone. I'm not sure if did that right and need some help on what to do.
 

Answers and Replies

  • #2
phinds
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I've started by shorting out both voltage sources and leaving only the current source in the circuit.
So how do you reckon the current will be the same with and without the voltage sources? That is, you have been asked to find the current WITH the voltage sources in the circuit but you have solved for the current having replaced the voltage sources with wires. How do you figure you'll get the same answer?
 
  • #3
So how do you reckon the current will be the same with and without the voltage sources? That is, you have been asked to find the current WITH the voltage sources in the circuit but you have solved for the current having replaced the voltage sources with wires. How do you figure you'll get the same answer?
Ahh I should have clarified that I was going to solve it again with the other sources still there while the current source becomes an open circuit. I guess my real question was if I got the right amount of current through the 3 ohm resistor using the current source alone, which that will be added to the other currents I get when using the seperate voltage sources alone.
 
  • #4
phinds
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Ahh I should have clarified that I was going to solve it again with the other sources still there while the current source becomes an open circuit. I guess my real question was if I got the right amount of current through the 3 ohm resistor using the current source alone, which that will be added to the other currents I get when using the seperate voltage sources alone.
Sounds crazy to me, and it's certainly not anything I ever have, or would ever, try, but I'm too tired to figure out if it's wrong. What I CAN say is that you sure are going about this the hard way, seems to me.
 
  • #5
gneill
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You're doing okay. Now work out the currents due to the other individual sources and sum the results.
 

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