Finding the Curvature of a Plane Curve

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To find the curvature of the plane curve r(t) = (3cost)i + (3sint)j at the point (√(2), √(7)), the formula κ=|r'(t) x r"(t)| / |r'(t)|^3 is typically used, but requires a three-dimensional approach for the cross product. Since the curve only has x and y components, it is suggested to add a 0k component to treat the vector as three-dimensional. Alternatively, κ can also be calculated using κ=|T'(t)/r'(t)|, which is suitable for two-dimensional curves. The discussion emphasizes the need to adapt the curvature formula to the dimensionality of the problem. Understanding these methods is crucial for accurately determining curvature in plane curves.
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Find the curvature of the plane curve given by r(t) = (3cost)i + (3sint)j at the point (√(2), √(7) ).

I know that κ=|r'(t) x r"(t)| / |r'(t)|^3
However, I believe that you are not allowed to do cross product unless there is an x, y, and z component and this question only has an x and y component.

In this case, am I supposed to use κ= |T'(t)/r'(t)| instead or use another formula all together?
 
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Just add a 0k to your vector and treat it as 3D if you want to use the cross product.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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