Finding the Electric Field given the potential in spherical

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SUMMARY

The discussion focuses on calculating the electric field (E) from the electric potential (φ) in spherical coordinates using the equation E = -∇φ. Participants express confusion regarding the differentiation process, particularly when applying the formula E = - (∂[p*r/4πε0r³]/∂r)er. A suggestion is made to switch to Cartesian coordinates for clarity, utilizing the relationships ∂r/∂x_i = x_i/r and ∂x_j/∂x_i. The final expression for the electric field is debated, with participants arriving at E = (p*er)/2πε0r³.

PREREQUISITES
  • Understanding of vector calculus, specifically gradient operations.
  • Familiarity with electric potential and electric field concepts.
  • Knowledge of spherical coordinates and their conversion to Cartesian coordinates.
  • Proficiency in applying Maxwell's equations in electrostatics.
NEXT STEPS
  • Study the derivation of electric fields from potentials in both spherical and Cartesian coordinates.
  • Learn about the application of the gradient operator in vector calculus.
  • Explore the implications of Maxwell's equations in electrostatics.
  • Review examples of electric field calculations for point charges and dipoles.
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Students and professionals in physics, particularly those studying electromagnetism, as well as educators looking for clarification on electric field calculations from potential functions.

John004
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Homework Statement


The problem statement is in the attachment

Homework Equations


E[/B] = -φ

= (∂φ/∂r)er

The Attempt at a Solution



I am confused about how to do the derivative apparently because the way I do it gives

E = - (∂[p*r/4πε0r3]/∂r)er = 3*(p*r)/4πε0r4er
 

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\mathbf{r} is not a constant.

I would suggest staying in Cartesian coordinates so that <br /> \frac{\partial \phi}{\partial x_i} = \frac1{4\pi\epsilon_0} \sum_j p_j \frac{\partial}{\partial x_i}\left(\frac{x_j}{r^3}\right) and using the results <br /> \frac{\partial r}{\partial x_i} = \frac{x_i}{r} and <br /> \frac{\partial x_j}{\partial x_i} = \begin{cases} 1, &amp; i = j, \\ 0, &amp; i \neq j.\end{cases}
 
Last edited:
pasmith said:
\mathbf{r} = r\hat{\mathbf{r}} is not a constant...
well if I plugged that in for r, wouldn't I just get

E = - (∂[p*rer/4πε0r3]/∂r)er = (p*er)/2πε0r3er ?
I haven't done vector calculus in a long time, idk if I am forgetting something obvious or what
 

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