Finding the Force Between Two Point Charges

AI Thread Summary
The discussion focuses on calculating the force between two point charges, +5μC and -100μC, separated by 15 cm. Using the formula F = q1q2 * k / r^2, the calculated force is 200 N. It clarifies that while each charge exerts a force on the other, the force is equal in magnitude and opposite in direction, meaning the net force in the system is zero. The term "force between two charges" specifically refers to the force one charge exerts on the other, which is 200 N. Thus, the correct interpretation of the force between the charges is 200 N, not 400 N.
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Homework Statement



Two point charges with charges of +5μC and -100μC are separated by 15 cm. The magnitude of the force between these charges is:

a) 1.99 N
b) 4.02 N
c) 20 N
d) 199 N
e) 400 N

Homework Equations



F = q1q2 * k / r^2

The Attempt at a Solution



F = (9.00*10^9)(5.0*10^-6 C)(1.0*10^-4 C) / (0.15 m)^2

F = 4.5 / 0.0225 m^2

F = 200 N

Why is it incorrect to think the force of one on two is 200 N and the force of two on one is 200 N so the force between them is 400 N?
 
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The phrase "force between two charges" is kind of fuzzy. It just means to find the force that one particle exerts on the other. The other particle will then exert the same magnitude of force on the first particle but in the opposite direction. [If for some reason you decided to add these two force vectors, what would you get?]
 
Aha! 0 N. (right?)
 
Right! The net force for the system is zero. Good. But the answer to the question "what is the magnitude of the force between them" would be "200 N". At least that's my interpretation!
 
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