Finding the impedance of a circuit

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SUMMARY

The discussion focuses on calculating the impedance of a circuit involving a 5 mH inductor and various other components. The initial approach of using the inductor's impedance as the total impedance was incorrect. Instead, the correct method involves applying Thevenin's Theorem to find the equivalent impedance between nodes a and g, considering the parallel combination of elements and the series capacitor between nodes a and b. The final impedance calculation requires analyzing the three branches in parallel between nodes a and g.

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Homework Statement


http://img297.imageshack.us/img297/2951/picqk5.th.jpg

I'm just trying to do part a for the moment.

Homework Equations





The Attempt at a Solution



My initial attempt was just trying to find the impedance of the 5 mH inductor and saying that would be Zin. Unfortunately that doesn't seem to be the case.

Then I tried doing a thevenin type problem where I find the impedance of all the elements to the right of the inductor, but that doesn't seem to work either.

I also just tried finding Zeq for the whole thing but that doesn't work either, hmm.
How does one find the impedance between two nodes? I would have thought that the 2nd method would have worked for sure.
 
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Thevenin Theorem should work here. Find the equivalent impedance seen from the nodes a and g.

(Hint : Fold from the right side to the left side)
 
No need to use Thevenin, since there is no power source.
Between nodes b and g there are two elements. Find the impedance of the parallel combination. Between nodes a and b there is a capacitor, that is in series with the impedance bg. Finally, calculate the impedance of the three branches in parallel between nodes a and g.
A similar reasoning can be made for items b and c.
 

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