OPAmp Impedance Circuit problem

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Discussion Overview

The discussion revolves around a problem involving an operational amplifier (OpAmp) circuit, specifically focusing on determining the equivalent impedance of the circuit and deriving certain component values as functions of others. The scope includes theoretical analysis and circuit design considerations.

Discussion Character

  • Technical explanation, Conceptual clarification, Debate/contested

Main Points Raised

  • One participant expresses difficulty in determining the equivalent impedance of the OpAmp circuit, despite being able to find the impedance of the equivalent circuit.
  • Another participant notes that they have not encountered an OpAmp configuration with both inputs inverting and questions the validity of the results, suggesting a possible change to a non-inverting input for better analysis.
  • A different participant describes the role of resistors and capacitors in forming a potential divider that influences the input voltage at the non-inverting input of the OpAmp.

Areas of Agreement / Disagreement

There appears to be no consensus on the configuration of the OpAmp circuit, with differing opinions on whether the analysis should involve a non-inverting input. The discussion remains unresolved regarding the best approach to take.

Contextual Notes

Participants have not fully explored the implications of the OpAmp's ideal assumptions, and there may be missing assumptions regarding the circuit configuration and component interactions.

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I'm trying to solve this problem and the first 2 questions on it are giving me a tough time. Picture Attached.

(1) Determine the equivalent impedance Zeq of the OpAmp circuit. Assume that the OpAmp
is ideal.

(2) Determine Rx, Lx, and Ry as a function of R, R1, and C such that Zeq of the equivalent
circuit is equal to Zeq of the OpAmp circuit.

any help with this is much appreciated. I can find the impedance of the equivalent circuit no problem but the opAmp version is tripping me up.
 
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forgot to attach in previous post here's picture
 

Attachments

I haven't seen an op-amp with both inputs inverting, before this. Okay, so I've lived a sheltered life. :smile:[/color]

Therefore, I have serious doubts about it giving the desired results. I think you might have to change the lower input to non-inverting (+). Does that make its analysis more in line with your expectations?
 
R and C form a potential divider, dividing the input voltage and impressing it on the (+) input of the op-amp.
 

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