Finding the Iterative Function to Solve x3+x-1000=0

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The discussion focuses on finding an iterative function to solve the equation x^3 + x - 1000 = 0 within the interval [9, 10]. Participants suggest two potential iterative functions: x = 1000 - x^3 and x = (1000 - x)^(1/3). The second function is confirmed to work effectively for the iterative process. It is also noted that the iterative method converges when the derivative of the function satisfies the condition |df/dx| < 1. Additionally, an alternative method is proposed involving rewriting the equation to isolate x, which may simplify the iteration process.
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Homework Statement



The iterative method is used to find the approximate root of the equation x3 + x - 1000 = 0 in [9, 10]. What is the suitable iterative function?

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The Attempt at a Solution


How to find the iterative function and is there any conditions for one?
Thanks for helps.
 
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The iterative procedure is to calculate the next approximation of x from a function of the previous approximation: xi+1=f(xi). The iterative process can converge in a range of x where the derivative |df/dx |<1.

You can try the ways: x=1000-x3 or x=(1000-x)^1/3.
Which one works? And you can find other iterative functions for this equation. ehild
 
Last edited:
ehild said:
The iterative procedure is to calculate the next approximation of x from a function of the previous approximation: xi+1=f(xi). The iterative process can converge in a range of x where the derivative |df/dx |<1.

You can try the ways: x=1000-x3 or x=(1000-x)^1/3.
Which one works? And you can find other iterative functions for this equation.

The second one works ^^ Thank you very much. Your explanation is very clear:D
 
Using cubic root in an iteration process is not too nice. You can find an other method without that. Hint: write x^3-1000 in the form (x-10)(x^2+10x+100), and isolate x from the x-10 factor.

ehild
 
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