MHB Finding the Length of TN on a Tangent of the Curve y = x^2

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The discussion focuses on finding the length of segment TN on the tangent line to the curve y = x^2 at point P(3,9). The derivative dy/dx is calculated as 2x, yielding a slope of 6 at x = 3. The equation of the tangent line is established as y = 6x - 9, with point T determined to be (3/2, 0). The next step involves identifying point N, which is defined by the perpendicular line PN to the x-axis.

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The tangent P(3,9) on the curve y = x^2, cuts the x-axis at T and PN is perpendicular to the x-axis. Find the length of TN.

So far I have:

dy/dx = 2x
dy/dx = 6

y - 9 = 6(x - 3)
y = 6x - 9

Making point T (3/2, 0), but how do you find point N?

Thank you.
 
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We have got that PN is perpendicular to the x-axis what do we conclude ?
 

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