Finding the mass of earths troposphere

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The discussion centers on calculating the mass of Earth's troposphere using pressure and area formulas. The initial calculations contained errors, particularly in the use of area squared instead of just area, leading to incorrect units. Participants emphasized the importance of maintaining units throughout calculations to avoid mistakes, highlighting that force should be derived from pressure multiplied by area, not area squared. The correct approach involves using the surface area of the Earth and air pressure to derive the total mass accurately. Ultimately, the conversation reinforces the necessity of careful unit management in scientific calculations.
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I was wondering if I could find the mass of all the air in the local 9.8 g range. This is what I came up with.

P = F / A^2
Ma = PA^2
M = PA^2 / a
M = P(4πR^2)^2 / a
M = P(16π^2R^4) / a
M = (101325)(16π^2(6400000^4)) / (9.8)
M = 2.74e37 kgI know that can't be right, but what did I do wrong?
 
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Surface area of Earth = 500 Million km^2 = 500E12m^2
Air pressure, 101kPa = 10tons/m^2
Total mass = 10E3kg/m^2 * 500E12m^2 = 500E15 kg

hint, you have A^2, but area is already m^2
 
There is one more error. A = 4\pi R^2 \neq (4 \pi R)^2
 
mgb_phys said:
Surface area of Earth = 500 Million km^2 = 500E12m^2
Air pressure, 101kPa = 10tons/m^2
Total mass = 10E3kg/m^2 * 500E12m^2 = 500E15 kg

hint, you have A^2, but area is already m^2

Wait, I thought that the units were irrelevant from the formula.

Then why don't we say that?

P = F / L^2, instead of A^2 or LWH = V^3 ?
 
Last edited:
zeromodz said:
Wait, I thought that the units were irrelevant from the formula.
You have force = pressure/area^2 instead of pressure/area, I think you are getting cofused because pressure is N/m^2
 
@aeromodz
He did. When he converted from Pa to tons, he effectively divided by g. It is no technically correct to have the equal sign in that step.

And F = P*A, not P*A^2. That's what mgb_phys means by A already being m^2.

Finally, you never, ever ignore units. Do computations WITH the units, to make sure your answer is correct.

For example, if I follow your computations keeping units in place, I end up with final answer being in units of kg*m^2 instead of just kg, and that tells me there was a mistake.
 
K^2 said:
@aeromodz
He did. When he converted from Pa to tons, he effectively divided by g. It is no technically correct to have the equal sign in that step.

And F = P*A, not P*A^2. That's what mgb_phys means by A already being m^2.

Finally, you never, ever ignore units. Do computations WITH the units, to make sure your answer is correct.

For example, if I follow your computations keeping units in place, I end up with final answer being in units of kg*m^2 instead of just kg, and that tells me there was a mistake.

Okay thank you. I understand now. I just wasn't thinking.
 

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