Finding the max shear stress at a point on a plate (with a hole)

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SUMMARY

The discussion focuses on calculating the maximum shear stress at a point on a plate with a hole under tension using experimental data. The method involves applying Mohr's Circle to determine principal stresses, which are essential for finding maximum shear stress. The formula for maximum shear stress is given as τmax = (σ1 - σ2) / 2, assuming σ1 is the highest principal stress. Additionally, an alternative calculation method using stress components is provided: τmax = √[(σx - σy) / 2]2 + τxy2.

PREREQUISITES
  • Understanding of Mohr's Circle for stress analysis
  • Knowledge of principal stresses in plane stress conditions
  • Familiarity with shear stress calculations
  • Basic principles of mechanics of materials
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  • Study Mohr's Circle for visualizing stress transformations
  • Learn about calculating principal stresses in plane stress scenarios
  • Explore advanced shear stress analysis techniques
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Mechanical engineers, structural analysts, and materials scientists involved in stress analysis and design of components under tension.

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i need to find max shear stress at a point on a plate (with a hole) under tension. i found using experimental data the principle strains at the point but i need to find the max shear stress using this data to compare it with a result found analytically.

any suggestions?
 
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Are you considering this plane stress? If you are, you'll have two principal stresses. Think about Mohr's Circle for a second...The principal stresses lie in a plane with no shear stresses (they lie on the horizontal axis). So if you rotate around 90° in Mohr's circle, you'll get to the point of max shear (the highest point on the vertical axis). Geometrically speaking that is the same as saying

\tau_{max} = \frac{\sigma_1-\sigma_2}{2}

This also assumes that you follow the standard practice of numbering the highest principal stress as \sigma_1.

You can double check it by running the calculation with the regular stress components:

\tau_{max}=\sqrt{\left[ \frac{\sigma_x-\sigma_y}{2}\right]^2 + \tau_{xy}^2}
 
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