Finding the Maximum Mass Ratio for Elastic Collisions: A Quick Homework Problem

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SUMMARY

This discussion focuses on solving a physics problem involving elastic collisions between two objects of mass M and a smaller mass m. The velocities after the collisions are derived using the Law of Energy Conservation and the Law of Momentum Conservation. The final result shows that the maximum mass ratio M/m, where the velocity of m remains less than or equal to that of B, is calculated to be 2 + √5. The derived equations for the velocities after the collisions are v1 = (M - m)/(M + m) * u and v2 = 2m/(M + m) * u.

PREREQUISITES
  • Understanding of elastic collisions in physics
  • Knowledge of the Law of Conservation of Energy
  • Familiarity with the Law of Conservation of Momentum
  • Basic algebra for solving equations
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  • Study the principles of elastic and inelastic collisions in detail
  • Learn how to apply the Law of Conservation of Energy in various scenarios
  • Explore advanced problems involving multiple collisions
  • Investigate the effects of friction on collision outcomes
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Students studying physics, particularly those focusing on mechanics and collision theory, as well as educators looking for practical examples of elastic collisions.

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Homework Statement


IMG_20171225_053813~2.jpg

Both object A and B have mass M and are moving.
An object with mass of m and moving with velocity u collide with the object B elastically. (m < M)
Find the following after m collide with B
1) Velocity of m after bouncing back
2) Velocity of B
Then m collide with A and bounce back
3) The highest value of M/m that velocity of m is lesser than or equal to that of B
(Surface has no friction)

Homework Equations

The Attempt at a Solution


Using the Law of Energy Conservation and the Law of Momentum Conservation

##\frac{1}{2} m u^2 = \frac{1}{2} m v_1^2 + \frac{1}{2} M v_2^2##

##m u = -m v_1 + Mv_2##

After solving the equation, I get this

##v_1 = \frac{M - m}{M + m} u## (Answer for (1))

##v_2 = \frac{2 m}{M + m} u## (Answer for (2))

Then object m hit object A. The velocity of m then change into

##(\frac{M - m}{m + M})^2 u##

Velocity of m should be equal to that of B so m cannot reach B

##(\frac{M - m}{m + M})^2 u = \frac{2 m u}{m + M}##

##\frac{M}{m} = 2 + \sqrt{5}## (Answer for (3))

Is that correct?
 

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